Mass Defect of Hydrogen-2 Electron Binding Energy

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SUMMARY

The mass defect of the hydrogen-2 atom, based on the provided binding energy of 13.6 eV, can be calculated using the relationship between binding energy and mass defect. The relevant equation is nuclear binding energy = mass defect x c². By converting 13.6 eV to MeV and then to atomic mass units (amu), the correct mass defect is determined to be approximately 1.32 x 109 amu, although this result appears to be incorrect based on the calculations presented. The atomic mass of hydrogen-2 is given as 2.014102 u, which is essential for accurate calculations.

PREREQUISITES
  • Understanding of nuclear binding energy concepts
  • Familiarity with energy-mass equivalence (E=mc²)
  • Knowledge of unit conversions between eV, MeV, and amu
  • Basic proficiency in using scientific notation for calculations
NEXT STEPS
  • Learn about the conversion factors between eV and MeV, specifically 1 MeV = 1.074 x 10-3 amu
  • Study the derivation and application of the mass-energy equivalence principle
  • Explore detailed examples of calculating mass defects in nuclear physics
  • Investigate the properties and applications of hydrogen isotopes, particularly deuterium
USEFUL FOR

Students studying nuclear physics, educators teaching atomic structure, and researchers interested in the properties of hydrogen isotopes will benefit from this discussion.

rayray2216
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Homework Statement :

the binding energy for the electron in the ground state of hydrogen-2 is 13.6ev
what is the corresponding mass defect of the hydrogen atom in amu (atomic mass units)
not sure if you need atmoic mass of the hysgrogen atom its given to be 2.014102u

Relevant equations:

not really sure but i know that nuclear binding energy=Mass defect x c^2
so BE/c^2=Mass deffect

931.58=uc^2

The attempt at a solution:
Havent really got a clue how to start i thought you would just use the above formula but i feel i am wrong :s1 amu = 931.46 MeV/c2 = 0.93146 GeV/c2
1 MeV/c2 = 1.074 × 10–3 amu
Thus 13.6 eV = 13.6 x 10^-6 MeV
=>13.6 eV = 13.6 x 10^-6 x 1.074 x 10^-3 x (3 x 10^8)^2 amu
=>13.6 eV = 1.32 x 10^9 amu

but i feel this is very wrong
 
Last edited:
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im desperate can anyone help...point me in the right direction ?
 

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