- #1
zombieguy
- 12
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I would appretiate help with the following 2 questions, I think I've got must of the first one right (Or went off t a tangent) but I don't now where to start on the second question
1a) Calculate the flue gas composition if 100 kmol h-1 of a gas whose composition is given below are burnt with 10% excess air.
b) Calculate the mass flowrate of air used
CO-12.6%
CO2-2.6%
H2-41.6%
CH4-26.6%
O2-1.9%
N214.7%
2) Ethanol dehydration reaction is carried out in a reactor with the feed entering at 300oC
C2H5OH --> CH3CHO + H2
This is an endothermic reaction. The feed contain 90% mole % ethanol and the balance acetaldehyde. Heat is added to keep the temprature from dropping too rapidly. With a fraction of 30% and outlet temprature of 100oC.
Calculate the heat addition rate per 253 mol of the feed gas.
Below are the heat capacity data (KJ/mol-C)
Cp [C2H5OH] = 0.11
Cp [CH3CHO] = 0.08
Cp [ H2] = 0.029
Heat of reaction = 68.95 J
Take Reference Temprature = 25oCHere my Working out for question 1:
12.6CO2+6.3O2 -> 12.6CO2
41.6H2+20.8O2 -> 41.6H2O
26.6CH4+53.2O2 -> 26.6CO2+53.2H2O
Total CO2= 12.6+2.6+26.6=41.8
Total H2O=41.6+53.2=94.8
Total O2=(6.3+20.8+53.2)X1.1+1.9=90.23
Total N2=((79/21)X88.33)+14.7=346.99
After that i worked out the %'s eg. %CO2(41.8/573.82)X100=7.3% (I'd put all of my % up but I'm not sure I'm right upto this point at best)
1b) mrXmoles=mass
O2, 32X88.33=2826.56
N2, 28X332.3=9304.04
Total=12130.65
1a) Calculate the flue gas composition if 100 kmol h-1 of a gas whose composition is given below are burnt with 10% excess air.
b) Calculate the mass flowrate of air used
CO-12.6%
CO2-2.6%
H2-41.6%
CH4-26.6%
O2-1.9%
N214.7%
2) Ethanol dehydration reaction is carried out in a reactor with the feed entering at 300oC
C2H5OH --> CH3CHO + H2
This is an endothermic reaction. The feed contain 90% mole % ethanol and the balance acetaldehyde. Heat is added to keep the temprature from dropping too rapidly. With a fraction of 30% and outlet temprature of 100oC.
Calculate the heat addition rate per 253 mol of the feed gas.
Below are the heat capacity data (KJ/mol-C)
Cp [C2H5OH] = 0.11
Cp [CH3CHO] = 0.08
Cp [ H2] = 0.029
Heat of reaction = 68.95 J
Take Reference Temprature = 25oCHere my Working out for question 1:
12.6CO2+6.3O2 -> 12.6CO2
41.6H2+20.8O2 -> 41.6H2O
26.6CH4+53.2O2 -> 26.6CO2+53.2H2O
Total CO2= 12.6+2.6+26.6=41.8
Total H2O=41.6+53.2=94.8
Total O2=(6.3+20.8+53.2)X1.1+1.9=90.23
Total N2=((79/21)X88.33)+14.7=346.99
After that i worked out the %'s eg. %CO2(41.8/573.82)X100=7.3% (I'd put all of my % up but I'm not sure I'm right upto this point at best)
1b) mrXmoles=mass
O2, 32X88.33=2826.56
N2, 28X332.3=9304.04
Total=12130.65