There is a steel beam of 1400kg hanging from the ceiling by two ropes. The first rope (R1) is 20 degrees to the left of the steel attach point, the second rope is 30 degrees to the right of the attach point.
Here is the diagram: http://img202.imageshack.us/img202/7654/06p29.jpg [Broken]
The relevant equations would be newton's second law, F = ma
Fx = F cos(theta)
Fy = F sin(theta)
This are all the relevant equations as far as I know.
The Attempt at a Solution
First, I found W (weight, the force of gravity on the object) by simply using newton's second law: F = ma where m = 1400kg and a = -9.8; with that I get W = -13720N
As the steel beam is not moving side to side, R1x = R2x Fnetx = 0
Because the tension is holding the steel beam in the air, the x-components of R1 and R2 must be equal to W. So: W = R1 cos 20 + R2 cos 30
Is this correct so far?
This is the part I get stuck. I know neither R1 or R2 and am not sure where to go.
Any help would be appreciated so much.
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