Mass launched into the air by a spring

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SUMMARY

The discussion revolves around calculating the spring constant (k) of a toy's spring using the formula 0.5kx² = mgh. The user initially calculated k as 258248.25 N/m but realized the answer was incorrect due to a unit conversion error and misunderstanding of energy distribution. The correct approach requires converting the maximum height from centimeters to meters and accounting for the potential energy used to elevate the toy to the spring's equilibrium position. The final corrected calculation should yield a more accurate value for k.

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Homework Statement


A child's toy consists of a piece of plastic attached to a spring in the figure below. The spring is compressed against the floor a distance of 2.00 cm, and the toy is released. If the toy has a mass of 117 g and rises to a maximum height of 45.0 cm, estimate the force constant of the spring. (Assume the toy rises 45.0 cm above the equilibrium position of the spring.)

Homework Equations


0.5kx^2 = mgh

The Attempt at a Solution



k = 2mgh/(x^2)

k = 2*0.117*9.81*45/(0.02^2)

k = 258248.25 N/m

Apparently this answer is off by a multiple of 10... not sure what's wrong. Can anybody help me? Thanks
 
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You forgot to convert 45 cm to meters. Also, some of the stored potential energy in the spring is used to raise the toy from where it starts to the equilibrium position. I am not sure if that will account for a factor of 10 though. More like a factor of 100.
 

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