# Homework Help: Mass of a particle through a magnetic field

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1. Jun 18, 2013

### aChordate

1. The problem statement, all variables and given/known data

In a mass spectrometer, the mass of charged objects is inferred from how much thier trajectory curves when passed through a perpendicular magnetic field. A particle has a charge of q=1.602x10^-19 C and is traveling at v = 2.00x10^5 m/s in a perpendicular magnetic field of B=100gauss. If the radius of the curvature is found to be 20.8 cm, what is the mass of the particle? & can you identify this particle?

2. Relevant equations

Fc=mv2/r

3. The attempt at a solution

Fc=m(2.00x10^5 m/s)2/r

I am guessing this is proton because of the positive charge.

2. Jun 18, 2013

### aChordate

Actually, I believe the equation is r= (mv)/(|q|B)

3. Jun 18, 2013

### aChordate

So, (0.208m)=(m*2.00x10^5m/s)/(1.602x10^-19*0.1 tesla)

and m = 1.67 x 10^-26 kg

Is this correct?

4. Jun 18, 2013

### Dick

0.1 tesla is 1000 gauss, not 100. Fix the exponent.

5. Jun 18, 2013

### aChordate

It would be 0.01 Tesla and the answer would be 6.49x10^14 ?

6. Jun 18, 2013

### Dick

It would be 0.01 tesla but now your answer is WAY off. You were closer before. What happened?

7. Jun 19, 2013

### aChordate

I think I made an algebraic error.

Now I have m=1.67x10^-27

8. Jun 20, 2013

### aChordate

And thanks for your help!