Mass of an accelerated electron?

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    Electron Mass
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Homework Help Overview

The problem involves an electron being accelerated from rest through a potential difference of 31 kV. Participants are discussing the implications of this acceleration on the mass of the electron and the energy involved in the process.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate the mass of the electron at rest to its mass when accelerated, using energy equations. Some participants question the terminology used, specifically whether "qV" refers to "QU" (charge times voltage).

Discussion Status

Some guidance has been offered regarding the relationship between energy gained by the electron and its mass. Participants are exploring the reasoning behind the equations used and confirming their understanding of the terms involved.

Contextual Notes

There is uncertainty regarding the correct application of formulas and the interpretation of energy terms. The discussion reflects a mix of attempts and clarifications without reaching a definitive conclusion.

Tryhard2
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Homework Statement


An electron is accelerated from rest through a potential difference of 31kV

Homework Equations


I don't know how to engage or solve a problem like this, I've done this attempt but I'm very uncertain that I've done it in a correct way, it's hard to understand if I've choosen correct forumulas etc it feels much like guesswork for me, but the final answer seem plausible as it is a small increase as it should, shouldn't it?

Have I done it right and have a good solution? if not, how do you solve such a problem?

My feeling was that if there is a mass while rest and another for acceleration I can add them together like this. But I'm not sure I have the right masses even.

The Attempt at a Solution


the electrons mass, m_0 = 9.109*10^-31 kg
Speed of light, c = 2.998*10^8 m/s

E=m_1*c^2 and E=QU give me:
m_1 = QU / c^2

m_1 = (1.602*10^-19) * 31000 / (2.998*10^8)^2 = 5.525*10^-32 kg

I then add m_1 and m_0 together giving me my final answer. m, m= m_0 + m_1
m = (5.525*10^-32) + (9.109*10^-31) = 9.66*10^-31 kg

Very thankful for input :)
 
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This is OK! The electron gains energy qV , so total energy will be: E = m0c2 +qV = m c2 or m = m0 + qV/c2
 
when you say qV? is that QU? (columb times volt) or something else

so essentially I did what you describe in the end?
 
Tryhard2 said:
is that QU?
Yes

Tryhard2 said:
so essentially I did what you describe in the end?
Yes, I just referred the reasoning for doing this...
 

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