Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P

  • Thread starter kevinnn
  • Start date
  • #1
kevinnn
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Homework Statement



Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P. I will just call that long mineral X.


Homework Equations





The Attempt at a Solution



I have no idea what is wrong.

(1.05 gP)*(1 molP/30.97 gP)*(1 molX/2 molP)*(873.68 gX/1 molX)= 14.8 gX What is wrong???
 

Answers and Replies

  • #2
kevinnn
119
0
Never mind. I calculated the same wrong molar mass twice in a row for the mineral.
 

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