Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P

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SUMMARY

The discussion focuses on calculating the mass of the compound Cu(UO2)2(PO4)2*8H2O, referred to as mineral X, needed to contain 1.05g of phosphorus (P). The user attempted to use stoichiometric conversions but repeatedly calculated the molar mass incorrectly. The correct calculation involves converting grams of phosphorus to moles, then using the stoichiometric ratio to find the mass of mineral X, resulting in a required mass of 14.8g.

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Homework Statement



Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P. I will just call that long mineral X.


Homework Equations





The Attempt at a Solution



I have no idea what is wrong.

(1.05 gP)*(1 molP/30.97 gP)*(1 molX/2 molP)*(873.68 gX/1 molX)= 14.8 gX What is wrong?
 
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Never mind. I calculated the same wrong molar mass twice in a row for the mineral.
 

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