Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P

[kevinnn]

Homework Statement

Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P. I will just call that long mineral X.

Homework Equations

The Attempt at a Solution

I have no idea what is wrong.

(1.05 gP)*(1 molP/30.97 gP)*(1 molX/2 molP)*(873.68 gX/1 molX)= 14.8 gX What is wrong???

 

[kevinnn]

Never mind. I calculated the same wrong molar mass twice in a row for the mineral.