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Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P

  1. Sep 10, 2013 #1
    1. The problem statement, all variables and given/known data

    Mass of Cu(UO2)2(PO4)2*8H2O required to contain 1.05g of P. I will just call that long mineral X.


    2. Relevant equations



    3. The attempt at a solution

    I have no idea what is wrong.

    (1.05 gP)*(1 molP/30.97 gP)*(1 molX/2 molP)*(873.68 gX/1 molX)= 14.8 gX What is wrong???
     
  2. jcsd
  3. Sep 11, 2013 #2
    Never mind. I calculated the same wrong molar mass twice in a row for the mineral.
     
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