1. The problem statement, all variables and given/known data a 1kg of Water at 25 degrees celsius is in a container. A solid block of 1kg Carbon Dioxide at its sublimation temp of -80 degrees celcious is placed into the container, with the lid then closed. Final temperature of entire system = 0 degrees celcius Final phase of the Carbon Dioxide is gas *What is the final mass of the liquid H20, solid H20, and gaseous H20? 2. Relevant equations Heat of Vap of Water = 2000 kj/kg Heat of Melt of Water = 300 kj/kg Csp of Water = 4 kj/kg Csp of CO2 gas = 1 kj/kg Heat of Sub of CO2 = 200 kj/kg [delta]Ethermal = mc[delta]T [delta]Ebond = ([delta]m)([delta]Heat of...) 3. The attempt at a solution From what I understand, the H20's conditions change as follows: Temp Initial = 25 degrees celcius Temp Final = 0 degrees celcious Phase Initial = Liquid Phase Final = Solid Thus, the H20 will have its thermal energy increasing and its bond energy increasing as well. As for the CO2's conditions: Temp Initial = -80 degrees celcius Temp Final = 0 degrees celcius Phase Intial = Solid Phase Final = Gas Since it is at it's sublimation temperature, it will skip over its intermediate state as a liquid and its thermal energy is increasing and its bond energy decreasing. So, to find the final mass of the liquid water, do I just use: [delta]Ethermal = Q mc[delta]t = Q (1kg)(4kj/kg K)(0celcius-25celcius) = Q -100 kj = Q [delta]m = Q/[delta]Heat of... [delta]m = -100/300 kg/kg <-- do I use Heat of melting for the liquid phase? What should be the next step I take in finding the mass of solid water and gaseous water?