Mass of Steam Needed for 1kg of Ice to Yield 20°C Water

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Homework Help Overview

The discussion revolves around calculating the mass of steam required to convert 1 kg of ice at 0°C into water at 20°C. The problem involves concepts from thermodynamics, specifically the latent heat of fusion and temperature change.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the latent heat of fusion and the relationship between the masses of steam and ice. There is an emphasis on clarifying the variables in the equation, particularly distinguishing between the mass of steam and the mass of ice.

Discussion Status

The conversation is focused on understanding the variables involved in the equation. Some participants have provided guidance on identifying the latent heat value and the need to clarify the mass terms. There is no explicit consensus yet, as participants are still exploring the definitions and relationships of the variables.

Contextual Notes

Participants are working under the assumption that the latent heat of fusion is known and are discussing how to apply it in the context of the problem. There is a noted need for clarity regarding the mass terms in the equation.

heelp
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what mass of steam at 100 c must be added to 1.ookg of ice to yeild liquid water 20c ?

this is what I have so for c*m* displacement of temperature =m *L
 
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You should know L (which I believe is 3.3 x 10^5 J/kg). Which is the Latent Heat of Fusion. You are given the mass of ice, change in temperature. Just solve for the second m in your equation. Which I'm assuming in the mass of the steam. When you have two of the same variables on each side of the equal sign, it looks confusing. Please denote "m of what".
 
Last edited:
m is the mass
 
I know that m is the mass. But you have an m on each side of the equal sign. What I'm asking you to state is the "mass of what". In your equation just solve for the m that relates to steam.
 

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