Mass on a vertical string - Conservation of Energy Problem

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Homework Help Overview

The problem involves a mass-spring system where a block is hung from a spring and subsequently pulled down and released. The subject area includes concepts of conservation of energy and spring mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct interpretation of the spring's stretch and how it relates to the energy equations provided. There is an exploration of the relationship between initial and final speeds and the displacement of the spring.

Discussion Status

Some participants have provided guidance on interpreting the problem statement more accurately, particularly regarding the amount of stretch in the spring. There is an acknowledgment of confusion around the problem's wording, but no consensus has been reached on the final calculations.

Contextual Notes

Participants note that the problem's phrasing may lead to misunderstandings about the spring's stretch and the initial conditions. There is an emphasis on the need to clarify the displacement from equilibrium rather than assuming a doubling of the stretch.

Bryon
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Homework Statement



https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/phys2111/fall/homework/Ch-08-GPE-ME/mass_vertical_spring/7.gif

A spring with spring constant k = 45 N/m and unstretched length of L0 is attached to the ceiling. A block of mass m = 1.5 kg is hung gently on the end of the spring.

a) How far does the spring stretch? Answer = 0.327m

Now the block is pulled down until the total amount the spring is stretched is twice the amount found in part (a). The block is then pushed upward with an initial speed vi = 2 m/s.

b) What is the maximum speed of the block? <---this one I am not sure of.

Homework Equations



0.5*m*v^2 = Ke
0.5*k*x^2 = K(spring)
U + K = Uo + Ko

The Attempt at a Solution



0.5*m*v(final)^2 = 0.5*m*v(initial)^2 + 0.5*k*x^2

for v I got 4.1 m/s. But the answer is incorrect. Any ideas where I went wrong?
 
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Your method for (b) is correct. At first I did what you did and got the same numbers as you. Then I reread the problem carefully. It is not very clear, but when it says "the block is pulled down until the total amount the spring is stretched is twice the amount found in part (a)", it means the spring is stretched from the unstretched position by twice the amount not from the new equilibrium by twice the amount. Try it.
 
Ah, ok so what I want to find is the length (L) of the relaxed spring with no force applied to it?
 
Bryon said:
Ah, ok so what I want to find is the length (L) of the relaxed spring with no force applied to it?
You don't need to find that, in fact you can't find that. All I'm saying is that the x in your last equation should be 0.327 m not 2*0.327 m. It represents the displacement from equilibrium when the mass is hanging and that is 0.327 m.
 
Ah, ok I had to read that a few times to understand it. That question is rather confusing, but I think i now see why its not twice the distance. Again, thanks for the help I truly appreciate the guidance!
 

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