Mass on an Incline with Spring Attached

[Tee01]

No $\Delta K$ is the change in kinetic energy of the block. I use the capital letter $K$ for kinetic energy. The one for the spring constant is the small letter $k$.

Thanks for having patience with me. I don't think I am capable of doing this question so i might just leave it.

 

[Delta2]

If you are not familiar with the work energy theorem and the concept of work then ok.

But then you can do at least 2a) with conservation of energy. Equate the gravitational potential energy to the maximum elastic potential energy of spring like i do in post #12.

 

[Tee01]

I did it and i get 0.5m for a) and 0.24m for b). used g=10m/s^2. Please post your workings here if you want me to comment on them.

I got x=2mgsin30/k and got 0.5 for a and 0.24 for b

 

[Delta2]

Ok but better to show me your work in order to be sure what you did exactly.

 

[Tee01]

Ok but better to show me your work in order to be sure what you did exactly.

Yea let me show you my working out

 

[Tee01]

Ok but better to show me your work in order to be sure what you did exactly.

 

[Delta2]

Ok, you did great, except one little thing, it is $\Delta K$=final kinetic energy-initial kinetic energy, not final-initial velocity. Other than that everything looks good, because the initial and final velocity are zero, the same holds for the initial and final kinetic energy.