Mass on incline will it slip or stick?

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SUMMARY

The discussion focuses on a physics problem involving a block of mass m on a 20-degree incline, connected to a 2.0 kg hanging mass via a massless string over a frictionless pulley. The coefficients of static and kinetic friction are uS=0.80 and uK=0.50, respectively. The minimum mass m that will stick without slipping is calculated incorrectly as 2.66 kg due to the omission of gravitational force in the analysis. For Part B, the correct approach involves using the kinetic friction coefficient to determine the acceleration once the block begins to move.

PREREQUISITES
  • Understanding of Newton's second law (Fnet=ma)
  • Knowledge of static and kinetic friction coefficients (uS and uK)
  • Ability to analyze forces on an inclined plane
  • Familiarity with basic mechanics concepts, including tension in strings
NEXT STEPS
  • Review the application of Newton's second law on inclined planes
  • Study the calculation of forces involving static and kinetic friction
  • Learn how to derive acceleration in systems with pulleys
  • Explore the effects of angle on friction and tension in connected mass systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined planes, as well as educators looking for examples of friction and tension problems in introductory physics courses.

charan1
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Homework Statement


Figure shows a block of mass m resting on a 20* slope. The block has coefficients of friction uS=0.80 and uK=0.50 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 2.0 kg.

Part A:
What is the minimum mass m that will stick and not slip?

Part B:
If this minimum mass is nudged ever so slightly, it will start being pulled up the incline. What acceleration will it have?

Homework Equations


Fnet=ma
us=F/N

The Attempt at a Solution



I really have no idea how to do Part B, but I tried part A and was real confident with my answer but it turned out wrong. This is what I did.

(2kg)(9.8)=19.6N for the hanging mass

assuming that the Hanging mass = to the tension force on the block with mass m I then did this...

19.6N=m(9.8)cos20*(.8)
m=2.66kg and this is wrong

Were did I go wrong?

Thanks
 

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Welcome to PF!

charan1 said:
Figure shows a block of mass m resting on a 20* slope. The block has coefficients of friction uS=0.80 and uK=0.50 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 2.0 kg.

Part A:
What is the minimum mass m that will stick and not slip?

Part B:
If this minimum mass is nudged ever so slightly, it will start being pulled up the incline. What acceleration will it have?

(2kg)(9.8)=19.6N for the hanging mass

19.6N=m(9.8)cos20*(.8)
m=2.66kg and this is wrong

Hi charan1! Welcome to PF! :smile:

(Useful tip: don't bother to multiply everything by 9.8 … all the terms have 9.8, so just call it g, and cancel it at the end. :wink:)

(oh … and have a mu: µ :smile:)

I take it you were applying Newton's second law in the direction of the slope.

That means that you must include all the forces … you left out the force due to gravity. :smile:

(For part B, use µK instead of µS)
 

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