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Introductory Physics Homework Help
Mass on inclined plane, string has mass
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[QUOTE="deekin, post: 4509975, member: 377692"] Thank you. So using the above suggestion, for the forces in the x-direction for the string, I have F - mgsinθ - F[SUB]string[SUB][/SUB][/SUB] = ma Now I add this to the expression for the force in the x-direction for the block and get F - mgsinθ - Mgsinθ = (M + m)a so solving for the acceleration, we get a = (F - (M + m)gsinθ)/(m + M). Then plugging this in, we get F[SUB]string[/SUB] - Mgsinθ = M(F - (M + m)gsinθ)/(m + M) Which means F[SUB]string[/SUB] = MF/(m + M). If I have missed something else, please let me know. Thank you so much for your help. [/QUOTE]
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Introductory Physics Homework Help
Mass on inclined plane, string has mass
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