Mass Ratio Q: Solving for Final Speed of 8km/s

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    Mass Ratio
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Homework Help Overview

The problem involves a single-stage rocket launched from a deep-space platform, focusing on calculating the mass ratio required to achieve a final speed of 8 km/s after burning fuel for 50 seconds, with a given exhaust speed.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the understanding of the rocket equation and its application to find the mass ratio. Questions arise about the nature of mass loss during fuel burn and whether it occurs at a constant rate. Some participants express uncertainty about how to manipulate the logarithmic equation involved.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem. Some guidance has been provided regarding the rocket equation, but there is still a lack of consensus on the specifics of the mass loss and its implications for the calculations.

Contextual Notes

Participants note that the problem does not specify whether the mass loss is constant, leading to further questioning of assumptions. The original poster has updated their question to seek clarity on the mass ratio and related calculations.

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Homework Statement


A single-stage rocket is fired from rest from a deep-space platform, where gravity is negligible.

If the rocket burns its fuel in a time of 50.0 s and the relative speed of the exhaust gas is v_ex=2100 m/s, what must the mass ratio m_{0}/m be for a final speed v of 8.00 km/s (about equal to the orbital speed of an Earth satellite)?

Homework Equations



v-v0= -v_exln(m/m0) = v_exln(m0/m)

The Attempt at a Solution



having a rough time understanding the equation, any tips or hints?

Any help would be greatly appreciated.
 
Last edited:
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I wonder if you are supposed to make a formula for the mass ratio as a function of time (it does vary). Is the mass lost at a constant rate?
 
It doesn't say that it has to be which i would assume it shouldn't be. All I know about the question is what you see. So to answer your question, i don't know. I was hoping someone would be able to answer that lol.
 
Does the rocket start from rest? If so, and you only care about the mass ratio and t=50 sec., then you just have to work out the log equation.
 
Yes, it appears that it is starting from rest. How would I go about finding the mass ratio? Also, the log equation?

How do I go about finding the mass of the rocket? (is that even the right question to ask)
 
Last edited:
updated the original question.
 
I'll help with the equation. It is known as the Tsiolkovsky rocket equation.

[tex]\Delta v = v_{\text{exhaust}}<br /> \ln\left(\frac{m_{\text{init}}}{m_{\text{final}}}\right)[/tex]

where

[itex]v_{\text{exhaust}}[/itex] is the exhaust speed relative to the rocket
[itex]m_{\text{init}}[/itex] is the initial (pre-burn) mass of the rocket
[itex]m_{\text{final}}[/itex] is the final (post-burn) mass of the rocket
[itex]\ln(x)[/itex] is the natural logarithm function.

The problem gives [itex]v_{\text{exhaust}}[/itex] and [itex]\Delta v[/itex] and simply asks for the mass ratio [itex]{m_{\text{init}}}/{m_{\text{final}}}[/itex]. Can you proceed with this?
 
Let me do the math really quickly and i'll show you what I got.
 
so is it MR=v_delta/v_exln?
 
Last edited:
  • #10
ok, i got it. thank you =)
 

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