Mass Ratio Q: Solving for Final Speed of 8km/s

[cycam]

Homework Statement

A single-stage rocket is fired from rest from a deep-space platform, where gravity is negligible.

If the rocket burns its fuel in a time of 50.0 s and the relative speed of the exhaust gas is v_ex=2100 m/s, what must the mass ratio m_{0}/m be for a final speed v of 8.00 km/s (about equal to the orbital speed of an Earth satellite)?

Homework Equations

v-v0= -v_exln(m/m0) = v_exln(m0/m)

The Attempt at a Solution

having a rough time understanding the equation, any tips or hints?

Any help would be greatly appreciated.

 

[gammamcc]

I wonder if you are supposed to make a formula for the mass ratio as a function of time (it does vary). Is the mass lost at a constant rate?

 

[cycam]

It doesn't say that it has to be which i would assume it shouldn't be. All I know about the question is what you see. So to answer your question, i don't know. I was hoping someone would be able to answer that lol.

 

[gammamcc]

Does the rocket start from rest? If so, and you only care about the mass ratio and t=50 sec., then you just have to work out the log equation.

 

[cycam]

Yes, it appears that it is starting from rest. How would I go about finding the mass ratio? Also, the log equation?

How do I go about finding the mass of the rocket? (is that even the right question to ask)

 

[cycam]

updated the original question.

 

[D H]

I'll help with the equation. It is known as the Tsiolkovsky rocket equation.

\Delta v = v_{\text{exhaust}}<br /> \ln\left(\frac{m_{\text{init}}}{m_{\text{final}}}\right)

where

v_{\text{exhaust}} is the exhaust speed relative to the rocket
m_{\text{init}} is the initial (pre-burn) mass of the rocket
m_{\text{final}} is the final (post-burn) mass of the rocket
\ln(x) is the natural logarithm function.

The problem gives v_{\text{exhaust}} and \Delta v and simply asks for the mass ratio {m_{\text{init}}}/{m_{\text{final}}}. Can you proceed with this?

 

[cycam]

Let me do the math really quickly and i'll show you what I got.

 

[cycam]

so is it MR=v_delta/v_exln?

 

[cycam]

ok, i got it. thank you =)