Massless particle revolving in a circle

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SUMMARY

The discussion centers on calculating the Y-axis acceleration of a massless particle revolving in a circle with a rotational velocity defined as (2 + sin(a)). Two methods are presented for determining Y-axis acceleration: Method #1 yields Y-axis acceleration = (2 + sin(a))(cos(a))^2, while Method #2 results in Y-axis acceleration = (2 + sin(a))(cos(a))^2 - (sin(a))(2 + sin(a)). The participants seek clarification on the correct method and the meaning of the variables involved, particularly the angle 'a' and the context of Y-axis acceleration in relation to the particle's motion in the xy-plane.

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Given: A massless particle revolving in a circle with a rotational velocity = (2+sin(a))
To Find: Y-axis acceleration
Method #1 (from rotational acceleration)
Y-axis acceleration = (2+sin(a))(cos(a))^2
Method #2 (from Y-axis velocity)
Y-axis acceleration = (2+sin(a))(cos(a))^2-(sin(a))(2+sin(a))

Which Y-axis acceleration is correct and why?

Can someone explain this?
 
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rotational velocity = (2+sin(a))
What does this mean? Is a an angle? If so what angle?
And what do you mean by "y-axis" acceleration? Are we to assume that the circle is in the xy-plane and you are looking for the y-component of acceleration?
 
HallsofIvy said:
What does this mean? Is a an angle? If so what angle?
And what do you mean by "y-axis" acceleration? Are we to assume that the circle is in the xy-plane and you are looking for the y-component of acceleration?

You tell me. I have no clue what they are asking. :cry:
 
Post the problem EXACTLY as it appears in your text/homework. Attach any pictures that come with the problem (or describe them).
 

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