I have wondered how a photon could be massless, given E=mc2. I have seen explanations involving treatment of the situation through consideration of momentum. It seems to me my own explanation is valid, and I ask for comments.(adsbygoogle = window.adsbygoogle || []).push({});

Actually E= m’c2 =gmc2, where g=1/sq rt{(1/[1-(v2/c2)]}. Photons travel at v = c, so the denominator is zero, making the equation invalid at the speed of light, thus eliminating the apparent conflict.

John

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# I Massless photon

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