Master Integrals with Substitution: Simplifying Tricky Integrals in Calculus

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caljuice
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∫dx
--------------------- (divide by)
(x2+a2)3/2

Tried integrating with substitution with U = x2+a2)
Then dU = 2xdx
x = √(U-a2)

Leaving me with dU/ (2x) (U)3/2
= ∫dU/2
-----------------------
√(u-a2))(U)3/2

But that doesn't help either.

Do I need to use a table? Thanks for any help.
 
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