Given that n is a positive integer, prove ∫sin^n(x)dx=∫cos^n(x)dx from 0 -> pi/2
Perhaps sin^2(x)+cos^2(x)=1? Not sure.
The Attempt at a Solution
I honestly don't even know where to start. Should I set u=sin(x) or cos(x)? Doesn't seem to get the right answer either way...