Trigonometric Integrals by Substitution

3 replies · 2K views · last reply
awsalazar
Messages
2
Reaction score
0
I am unsure whether I have properly performed the integration of the integral ∫((sin(√x))^3*dx)/√x

When I used my TI-Nsprire CAS to take the derivative of my answer in order to check if I was correct, and it came out differently. Now I used some trig identities to manipulate the problem, so I figured that is why it was different. So when I stored the integral into one function and the solution into another function, values I would enter were different for each function. Can someone correct any errors I have made or confirm that my answer is correct?

I have attached my attempt at the integral as a .jpg file.
∫((sin(√x))^3*dx)/√x
 
Attachments
  • Handwritten integration by substitution of the integral of sin cubed of the square root of x over the square root of x dx, with a substitution table for u = sqrt(x), v = cos u, followed by steps reducing to 2/3 cos cubed of sqrt(x) minus 2 cos sqrt(x) plus C.
    Trig Integral.jpg
    19.8 KB · Views: 552
Last edited:
Your solution and answer are correct. Note that whatever answer your calculator had, you can merely subtract it from the original and see if the result is 0.
 
Thanks a lot guys, and good advice Karnage1993, a much easier process then what I was doing.