Master Logarithmic Equations: Expert Tips for Solving Problems

Click For Summary

Homework Help Overview

The discussion revolves around solving logarithmic equations, with participants expressing challenges in manipulating the equations and understanding the relationships between the numbers involved.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss whether to equate numbers or manipulate them through multiplication. There are suggestions to take logarithms and rewrite equations in different forms, as well as considerations of variable substitutions.

Discussion Status

The discussion is active, with participants offering partial guidance and exploring various interpretations of the equations. There is no explicit consensus, but multiple approaches are being considered.

Contextual Notes

Some participants express confusion about the notation used in the equations, particularly regarding the interpretation of logarithmic expressions. There is also a mention of needing to clarify assumptions about the numbers involved.

bluff_boy
Messages
2
Reaction score
0
Having problems with these questions, what's putting me off is for example the first question, if the numbers 9 and 5 were the same I think I could do it. Do I have to get them to the same number or do I just multiply them?
 

Attachments

  • problem.png
    problem.png
    2.5 KB · Views: 469
Physics news on Phys.org
For (1). Take log of both sides and use logarithm rules.

That's about all the help I'm giving you right now. You make an effort now.
 
For (ii), multiply both sides by et. Let w = et, and rewrite the equation in terms of w. What does the resulting equation look like now?
 
bluff_boy said:
Having problems with these questions, what's putting me off is for example the first question, if the numbers 9 and 5 were the same I think I could do it. Do I have to get them to the same number or do I just multiply them?

(i) lhs= 125*[9^3 *5^2]^x = 125* 18225^x
rhs = 3^3*2^4/5^2 *[3^4/2/5^3]^x = (432/25)(81/250)^x.
Thus, [18225*250/81]^x = (432/25)/125.

(ii) Put x = exp(t) and see what you get.

(iii) Put x = ln(i+2). First you need to decide if [itex]\ln(i+2)^6[/itex] means [itex]\ln [(i+2)^6][/itex] or [itex][ \ln (i+2) ]^6 .[/itex]

RGV
 

Similar threads

Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 26 ·
Replies
26
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
22
Views
3K
  • · Replies 14 ·
Replies
14
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K