Mastering Functional Derivatives in Quantum Field Theory

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SUMMARY

This discussion focuses on mastering functional derivatives in Quantum Field Theory (QFT), specifically in the context of deriving Feynman rules for models like \(\phi^{4}\). The user struggles with the application of functional derivatives, particularly in handling exponential functions and the associated factors that arise during differentiation. Key expressions discussed include the Feynman propagator \(\Delta_{F}(x-y)\) and the manipulation of terms involving \(J\) and \(\Delta\). The user ultimately seeks resources to clarify these concepts and improve their understanding of functional derivatives.

PREREQUISITES
  • Understanding of Quantum Field Theory (QFT)
  • Familiarity with Feynman rules and propagators
  • Knowledge of functional derivatives and their properties
  • Basic proficiency in calculus, particularly with exponential functions
NEXT STEPS
  • Study the derivation of Feynman rules in Quantum Field Theory
  • Learn about functional derivatives and their applications in QFT
  • Examine examples of exponential functions in the context of functional calculus
  • Review operator calculus and its relation to functional derivatives
USEFUL FOR

This discussion is beneficial for students and researchers in Quantum Field Theory, particularly those grappling with the complexities of functional derivatives and their applications in deriving Feynman rules.

Elwin.Martin
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Alright, so I feel kind of dumb...but:

I have been working on some QFT material, specifically derivation of Feynman rules for some more simple models (\phi^{4} for example), and I have been seriously failing with functional derivatives. Every time I try to use the definition I mess up somewhere. Usually, my best bet is to sort of treat it like a regular derivative and use some intuition, but that's not really legitimate.

Oh, the Δ here is the Feynman propagator, I'm not sure what the standard is for notation so I suppose I should mention that.

Take for example \frac{1}{i}\frac{\delta}{\delta J(z)} exp\left[-\frac{i}{2}\int J(x)\Delta_{F}(x-y)J(y)dxdy\right]

So what I'm supposed to get is
- \int \Delta (z-x)_{F} J(x) dx \ exp \left[-\frac{i}{2} \int J(x) \Delta_{F}(x-y)J(y)dx dy \right]

And I can rationalize it as that we have an exponential and we treat exponential derivatives as we do traditionally, but then I get confused with where my factor of 1/2 went from the exponent...clearly, the i's cancel, but where did the two go? I have a feeling it has to do with the repeat of the J's in the J Δ J but I'm not sure.

Ugh. . .this has wasted so very much of my time.

Not to mention, I've yet to convince myself that we ARE allowed to treat an exponential the same way, though I think I might have an idea how to show it, I'm not sure how common identities like product rule would be proved with functionals.

If someone could give me something to read over or something that would be awesome. I've looked for a while and not found much help. I found a paper by Feynman on Operator Calculus that had an Appendix relating to functionals but that didn't really help ^^;...
 
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you could start with an example like

\frac{\partial}{\partial x_i}\text{exp}\left[-\frac{1}{2}\,x_m\,A_{mn}\,x_n\right]

with a symmetric matrix A and a sum over indices m,n
 
tom.stoer said:
you could start with an example like

\frac{\partial}{\partial x_i}\text{exp}\left[-\frac{1}{2}\,x_m\,A_{mn}\,x_n\right]

with a symmetric matrix A and a sum over indices m,n

Okay, so the 1/2 gets absorbed in quadratic terms for m=n and then absorbed in the symmetry otherwise.

And for my case we treat the JΔJ term likewise. . .Wait that looks familiar .-. I lose.

Like the form \int exp \left[ \frac{-1}{2} \int \phi (x) A \phi (x)dx\right]

with A being a differential operator we get (det A)-1/2 .-. I'm an idiot, I've seen this before and forgot. I thought that the discrete problem you typed looked familiar.

Thank you!
 

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