- #1
jaychay
- 58
- 0
Can you please help me ?
I have tried to do it many times but I end up getting the wrong answer.
Thank you in advance.
MHB Mastering Partial Differentiation: A Comprehensive Guide
- Thread starter jaychay
- Start date
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The discussion centers on confusion between integration by parts and partial differentiation. A user initially struggles with a differentiation problem but ultimately arrives at the correct product rule formula for derivatives. They then express that the problem relates more to integration by parts rather than partial differentiation. This highlights a common misunderstanding in calculus concepts. The conversation emphasizes the importance of correctly identifying the mathematical operation required for problem-solving.
Can you please help me ?
I have tried to do it many times but I end up getting the wrong answer.
Thank you in advance.
- #2
jaychay
- 58
- 0
I finally got the answer to the question.
- #3
skeeter
- 1,103
- 1
$\dfrac{d}{dx}[f(x)h(x)] = f’(x)h(x) + f(x)h’(x)$
$\displaystyle f(x)h(x) = \int f’(x)h(x) \, dx + \int f(x)h’(x) \, dx$
$\displaystyle (x+1)^5 = \sin{x} + \int f(x)h’(x) \, dx$
finish it ...
$\displaystyle f(x)h(x) = \int f’(x)h(x) \, dx + \int f(x)h’(x) \, dx$
$\displaystyle (x+1)^5 = \sin{x} + \int f(x)h’(x) \, dx$
finish it ...
- #4
HOI
- 921
- 2
I think this is a problem on "integration by parts", NOT "partial differentiation".
Hello!
I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem.
Given:
##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0##
##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1##
##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0##
I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...
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