- #1

kramerbaggins

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## Homework Statement

A 1500 kg weather rocket accelerates upward at 10m/s^2. It explodes 2.0 s after liftoff and breaks into two fragments, one twice as massive as the other. Photos reveal that the lighter fragment traveled straight up and reached a maximum height of 530 m.

That is the problem.

What was the speed of the heavier fragment just after the explosion?

That is the question.

I solved and got 20.96 m/s. It gives me this error:

You are close. You may have made a rounding error or used the wrong number of significant figures.

## Homework Equations

Using the 10m/s^2 * 2s, i got the v_i to be 20 m/s, p_i then is 30000 kg*m/s.

p_f is 1000*v_f_1 + 500*v_f_2

Used v_f^2 = v_i^2 + 2*a*s on the smaller mass fragment. Used v_f = 0, a = -9.8, s given in problem. Solved for v_i. This v_i is the inital velocity of the fragment, aka its velocity at the end of the explosion.

Set 30000 = 1000*v_f_1 + 500*v_f_2, using v_f_2 from dynamics equation work above. solved for v_f_1.

## The Attempt at a Solution

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