Mastering physics: The Electric Field at a Point Due to Two Point Charges

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SUMMARY

The discussion focuses on calculating the net electric field at the origin due to two point charges: q1 at (-4.00 nC) located at (0.600, 0.800) meters and q2 at (+6.00 nC) located at (600, 0) meters. The correct approach involves calculating the electric fields E1 and E2 using the formula E = K|q|/r², where K is the Coulomb's constant (8.988 x 10^9 N m²/C²). The participant calculated E1 as 35.95 N/C but struggled with determining the angle of the net electric field relative to the negative x-axis.

PREREQUISITES
  • Understanding of electric fields and point charges
  • Familiarity with Coulomb's law and the constant K (8.988 x 10^9 N m²/C²)
  • Knowledge of vector addition in physics
  • Ability to perform trigonometric calculations for angles
NEXT STEPS
  • Learn vector addition of electric fields in multiple dimensions
  • Study the concept of electric field direction and angles
  • Explore the effects of multiple point charges on electric fields
  • Practice problems involving electric fields and point charges using different configurations
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone looking to deepen their understanding of electric fields and point charge interactions.

silver421
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Homework Statement


A point charge q1:-4.00 nC is at the point x=0.600 meters, y=0.800 meters, and a second point charge q2:+6.00 nC is at the point x=600 meters, y=0 .

a) Calculate the magnitude of the net electric field at the origin due to these two point charges.
Express your answer in Newtons per coulomb to three significant figures.

b) What is the direction, relative to the negative x axis, of the net electric field at the origin due to these two point charges.
Express your answer in degrees to three significant figures.

\phi= _________ (up from the negative x axis)


Homework Equations





The Attempt at a Solution


I tried calculating E1 and E2 and added them both to get E but my answers are wrong
 
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That is the correct way, as long as you take into account the fact that the electric field has a direction as well.

Can you show us how you calculated, for example, E1?
 
i used the equation E=K|q|/r^2. i used these numbers K= 8.988x10^9 q= 4.00x 10^-9 nC
r= square root of: (0.600)^2 + (0.800)^2
and i got E1= 35.95

and for the angle part i have no idea how to do it!
 

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