[Material Science] Thin Walled Cylinders & Yield Criterion

AI Thread Summary
The discussion focuses on calculating the internal pressures that will cause yield in a thin-walled cylindrical boiler shell using various yield criteria: Rankine, Maximum Principal Strain, Tresca, and Von Mises. The user initially struggles with the Von Mises criterion, obtaining an incorrect value of 3.11 MPa instead of the expected 4.75 MPa. After researching, they find a simplified equation that yields the correct answer. The user realizes their error in algebra related to the cross terms in the yield equation. The conversation concludes with a focus on moving forward to the failure criterion.
MarleyDH
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Homework Statement



A long cylindrical boiler shell is 1.75 m in diameter and has a wall thickness of 12 mm. Treating the boiler as a thing shell, predict what internal pressures will produce yield in the shell according to the: (a) Rankine, (b) Max. Principal Strain, (c) Tresca and (d) Von Mises Criteria.

σyield = 300 MPa, E = 200 GPa, v = 1/3)

Homework Equations



The only issue I am having here is with the Von Mises criteria, which states for plane stress:

σ12 + σ1·σ2 + σ22 = σyield2

σhoop = P·D/2·t
σaxial = P·D/4·t

The Attempt at a Solution



So all good and well, I attempt the solution but get a value of 3.11 MPa, which is incorrect according to the answer. (4.75 MPa)

I then rechecked my results and did a google search. This lead me to a site which boiled the math down to a similar problem to:

σyield = sqrt(3)·(P·D/4·t)

When I use this equation, I get the correct answer.

I then reattempted my algebra and get to this:

(P·D/2·t)2 + (P·D/2·t)·(P·D/4·t) + (P·D/4·t)2 = σyield2

What am I missing here?

Any help would be appreciated.

Thank you,

- MarleyDH
 
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MarleyDH said:
σ12 + σ1·σ2 + σ22 = σyield2
Wrong. Read more carefully.
 
Ah right. Saw my mistake, the cross terms should be a preceded with a minus sign. Thanks for the assistance once again nvn. Now its on to failure criterion!
 
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