MHB Math Cumulative Review: Find the equation of a Line

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To find the equation of a line perpendicular to y = -1/2x - 5 and passing through the point (6, -4), the slope of the perpendicular line must be the negative reciprocal of -1/2, which is 2. The point-slope form of the equation is used: y - (-4) = 2(x - 6). Simplifying this gives the equation y = 2x - 16. Therefore, the correct answer is option 4, y = 2x - 16.
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Hey there! Currently struggling through a cumulative review, so I will posting a lot more questions.

An equation of a line perpendicular to the line represented by the equation y= -1/2x-5 and passing through (6, -4) is

1) y= -1/2x + 4
2) y= -1/2x - 1
3) y= 2x + 14
4) y= 2x - 16

I know it's not 1 or 2 because perpendicular lines have to be negative reciprocals. What I don't know is how to figure out whether the answer is 3 or 4.
 
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point-slope form ...

$y-y_1 = m_{\perp}(x -x_1) \implies y-(-4) = 2(x-6)$

simplify
 
Mathlete said:
Hey there! Currently struggling through a cumulative review, so I will posting a lot more questions.

An equation of a line perpendicular to the line represented by the equation y= -1/2x-5 and passing through (6, -4) is

1) y= -1/2x + 4
2) y= -1/2x - 1
3) y= 2x + 14
4) y= 2x - 16

I know it's not 1 or 2 because perpendicular lines have to be negative reciprocals. What I don't know is how to figure out whether the answer is 3 or 4.

You are also told that when x= 6, y= -4. What do you get for y when you put x= 6 in either (3) or (4)?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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