Math Homework Woes: Extra Credit Assignment for My Son

Click For Summary
SUMMARY

The forum discussion revolves around a math homework assignment involving limits and growth rates. The first problem requires calculating the age at which a son, currently 8 years old and 54 inches tall, would reach 10 feet tall if he grows 1 inch the first week, 1/2 inch the second week, and so on. The second problem asks for the limit of height growth if he grows 1 inch the first week, 1/4 inch the second week, and 1/9 inch the third week. The discussion highlights the use of factorials (n!) and the harmonic series in solving these problems.

PREREQUISITES
  • Understanding of factorial notation (n!)
  • Familiarity with the harmonic series and its properties
  • Basic knowledge of limits in calculus
  • Ability to work with infinite series and convergence
NEXT STEPS
  • Study the properties of the harmonic series and its divergence
  • Learn about the concept of limits in calculus, specifically L'Hôpital's rule
  • Explore the relationship between growth rates and limits in mathematical sequences
  • Investigate the applications of factorials in combinatorial mathematics
USEFUL FOR

Students tackling advanced math problems, educators seeking to explain concepts of growth and limits, and anyone interested in the applications of calculus in real-world scenarios.

Fatentity
Messages
3
Reaction score
0

Homework Statement


It's an extra credit assignment assigned by my math teacher, I sort of tried it but I'm not very good, and not too sure what else to do, this part isn't my strong suit.
Here's the problem:
(A)
"If my son would live forever and he grows 1 inch this week, 1/2 inch next week, 1/3 inch the week after that, ...etc. Then how old would my son be when he finally reaches 10 feet tall?
(Note: He's already 8 years old and 54 inches tall.)
(B) "If my son grows 1 inch this week, 1/4 inch next week, 1/9 inch the next week afte that, ...etc. Then what is the limit to how tall my son will grow (ie. What height will he get closer and closer to but never attain even if he lives forever?)

Homework Equations



http://en.wikipedia.org/wiki/Factorial

The Attempt at a Solution



I know it has to do with factorial (n!) and the n=1, 1/n and that side ways M thing *I forget the name*.

I tried...(Not sure how I can write that symbol)
Sn = /n!
1/n = 1+1/2+1/3+1/4...+1/n. 1 3 11 50
S(1) = 1
S(2) = 1 + 1/2 = 3/2 2x3x-3
S(3) = 1 + 1/2 + 1/3 = 11/6 4x3-1
S(4) = 1 + 1/2 + 1/3 + 1/9 = 35/18

So, I know the bottom is just n!, but I'm not sure about the top.

Besides that I'm not really too sure what to do. Help please! Thank you in Advance =].
Sorry I don't have much more work to show, just not too sure where to go.
 
Physics news on Phys.org
Fatentity said:

Homework Statement


It's an extra credit assignment assigned by my math teacher, I sort of tried it but I'm not very good, and not too sure what else to do, this part isn't my strong suit.
Here's the problem:
(A)
"If my son would live forever and he grows 1 inch this week, 1/2 inch next week, 1/3 inch the week after that, ...etc. Then how old would my son be when he finally reaches 10 feet tall?
(Note: He's already 8 years old and 54 inches tall.)
(B) "If my son grows 1 inch this week, 1/4 inch next week, 1/9 inch the next week afte that, ...etc. Then what is the limit to how tall my son will grow (ie. What height will he get closer and closer to but never attain even if he lives forever?)

Homework Equations



http://en.wikipedia.org/wiki/Factorial

The Attempt at a Solution



I know it has to do with factorial (n!) and the n=1, 1/n and that side ways M thing *I forget the name*.
Sigma is the name of this Greek letter - \Sigma
Fatentity said:
I tried...(Not sure how I can write that symbol)
Sn = /n!
1/n = 1+1/2+1/3+1/4...+1/n. 1 3 11 50
What's the purpose of 1, 3, 11, 50?
Fatentity said:
S(1) = 1
S(2) = 1 + 1/2 = 3/2 2x3x-3
S(3) = 1 + 1/2 + 1/3 = 11/6 4x3-1
S(4) = 1 + 1/2 + 1/3 + 1/9 = 35/18

So, I know the bottom is just n!, but I'm not sure about the top.
I think this is what you're trying to do. Here S(n) is the sum of the first n terms, 1 + 1/2 + 1/3 + ... + 1/n.
S(n)~=~\sum_{k = 1}^n \frac{1}{k}~=~1 + 1/2 + 1/3 + ... + 1/n
The common denominator for the terms in the expanded summation is n!, but I'm not sure how you can use that fact.
Fatentity said:
Besides that I'm not really too sure what to do. Help please! Thank you in Advance =].
Sorry I don't have much more work to show, just not too sure where to go.
 
It's going to be a long time. He has 66 more inches to go. Your sum:

Sn= 1 + 1/2 + ... + 1/n

doesn't have a nice simple closed form But it can be shown to be greater that ln(n). How large does n need to be for ln(n) > 66?
 

Similar threads

Replies
13
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K