Math Practice: Periodic Functions

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The discussion centers on a user seeking help with a math practice exam, specifically regarding the transition from step b to step c in finding (del)u(x,y). The user has already emailed their professor for clarification and is looking for additional assistance. A respondent offers to help but notes the lack of context without the attached file. They suggest that understanding periodic functions involves identifying key characteristics and using calculus techniques for derivatives. The user is encouraged to provide more information or context for better assistance.
scariari
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I'm doing a practice exam for a math test on thursday, wondering if anyone could help figure out how to get from one step to the next. i don't think that the background info is necessary for these two steps.

the file is attached (Adobe acrobat).

what i am wondering about is the answer under (2b).
If the solution for finding (del)u(x,y) were lettered a through d (4 steps, i am wondering how the professer got from b to c.

of course i have emailed him as well.
 

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Look in the last line of the 2b) paragraph.
<br /> \Delta \frac{16}{\pi^4 kl(k^2+l^2)}sin(k \pi x)sin(l \pi y) =
\frac{16}{\pi^4 kl(k^2+l^2)}(-\pi^2 (k^2 + l^2)sin(k\pi x)sin(l\pi y)) <br /> <br />

JMD
 
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Hi there,

I can definitely help you with understanding the steps for finding (del)u(x,y) in the practice exam. However, without the background information or the attached file, it is difficult for me to provide specific guidance. Can you please provide more context or share the file so I can see the steps and provide a clear explanation?

In general, the process for solving periodic functions involves identifying the period, amplitude, and phase shift, and then using these values to create a graph or an equation. From there, you can use calculus techniques to find the derivative, which is (del)u(x,y) in this case.

I recommend reaching out to your professor for clarification on the steps or providing more information for me to assist you further. Good luck on your test on Thursday!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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