Math used in this equation rearrangement?

  • Context: Undergrad 
  • Thread starter Thread starter MarchON
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the calculation of the mass of water required to raise a car's temperature from -25°C to 0°C, with water initially at 10°C. The relevant equation is derived from the principle of energy conservation, specifically the heat transfer between the car and the water, incorporating latent heat of fusion. The final rearranged equation for the mass of water is expressed as mw = -mcccΔTc / (cwΔTw + Lf,w). The participants clarify the algebraic steps and the significance of latent heat in the context of phase change from liquid to solid.

PREREQUISITES
  • Understanding of thermodynamics, specifically heat transfer principles.
  • Familiarity with latent heat of fusion and its implications in phase changes.
  • Basic algebra skills for manipulating equations.
  • Knowledge of specific heat capacity (cw) and its role in thermal calculations.
NEXT STEPS
  • Study the concept of latent heat of fusion in detail.
  • Learn about specific heat capacity and its calculation in thermal systems.
  • Explore energy conservation principles in thermodynamic processes.
  • Practice algebraic manipulation of equations in physics contexts.
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone involved in thermal energy calculations or heat transfer analysis.

MarchON
Messages
16
Reaction score
1
I'm trying to determine how much water it takes to raise a car's temperature from -25°C to 0°C. The water is at 10°C.

What I apparently need to have set up is:

-ΔUint,water = ΔUint,car

-(mwcwΔTw) - mwLf,w = mcccΔTc

The resultant rearranged equation looking for mass of water gives this:

mw = -(mcccΔTc)/cwΔTw - mwLf,w

I don't understand how this was done. Also, why are you subtracting Latent heat of fusion x Mass from mwcwΔTw?
 
Science news on Phys.org
Looks like there's a mistake in the algebra, then. What do you think that eqn should be?

Q for you: why does latent heat of fusion enter into the picture at all?
 
MarchON said:
The resultant rearranged equation looking for mass of water gives this:

mw = -(mcccΔTc)/cwΔTw - mwLf,w

Says who?

(Hint: are the units consistent?)
 
Latent heat of fusion is in the picture because the water is going from a liquid to a solid. It freezes when it hits the car, then at a certain point it doesn't because the car warms up to 0 degrees. And I don't know what's up with the equation, but that's what my professor's solution says. Based on my math, I got something that makes no sense:

0= mcarccarΔTcar/CwΔTw + Lf
 
The left side should be mw. You need a pair of brackets on the right side, and then it should look right.
 
I don't understand how. Is there any way (and I know this is no easy task) to break down the algebra step by step for me?
Also, I made a mistake with the resultant equation in my first post. It's actually mw = -(mcccΔTc)/cwΔTw - Lf,w (no - mwLf,w)

I realize that ends up being the same thing that you said and there is no error (but he kept the negatives in, whereas we canceled them out), but I still don't understand how.
 
You started with this: -mwcwΔTw - mwLf,w = mcccΔTc
Taking out a common factor -mw we have
-mw(cwΔTw +Lf,w)= mcccΔTc

Now divide both sides by (cwΔTw +Lf,w)
and we are left with
-mw = mcccΔTc / (cwΔTw +Lf,w)

Multiplying both sides by -1 so that we end up with mw by itself,
mw = -mcccΔTc / (cwΔTw +Lf,w)

The brackets I said you needed are those in the denominator; the ones you added in the numerator make no difference.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
22
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K