Mathematica Trouble: Solving for x in Sinc[x] > (1/1.01)

[Airsteve0]

If anyone on here uses Mathematica maybe you could help me with an issue I am having with computing the following:

Solving for x in: Sinc[x] > (1/1.01)

I am looking only at the positive values and not making any headway with the Solve or NSolve commands. I should also mention that this only makes sense for the angle being between 0 and Pi/2.

 

[Bill Simpson]

This
http://www.wolframalpha.com/input/?i=plot+sinc(x)+for+0+<+x+<+pi/2
shows there will be a single open interval where Sinc[x]>1/1.01 and 0<x<pi/2.

This
http://www.wolframalpha.com/input/?i=solve+sinc(x)==1/1.01+and+x>0
gives you the upper endpoint.

When you know there is a single simple interval for a solution then I would suspect that Mathematica might correctly accept

NSolve[Sinc[x]==1/1.01,x]

to give you that upper endpoint, but unfortunately I cannot verify that for you at the moment.

Note: There is the Math & Science Software section of the forum where many of the small questions about Mathematica syntax might be more quickly and better answered. Poke around several sections below the Math category and you will find it.

 

[Bill Simpson]

In[1]:= FindRoot[Sinc[x]-1/1.01,{x,.25}]

Out[1]= {x->0.244097}