Maths Notation: What Does \oint Mean?

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The symbol \oint denotes an integral over a closed curve, primarily used in contexts like line integrals in vector calculus. While some textbooks may use it in scenarios that aren't strictly closed, it generally signifies a closed path, especially in applications like the Biot-Savart law. The discussion highlights that \oint is not typically used for surface integrals unless explicitly stated, as seen in Gauss's Law, which requires a closed surface. The consensus is that \oint should indicate closed paths or surfaces to maintain clarity in mathematical expressions. Understanding this notation is crucial for correctly interpreting integral equations in physics and engineering contexts.
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This is probably a dumb question but what does the circle through the integral sign mean?
\oint

I was thinking perhaps it could denote either the line integral over a closed curve, or the surface integral over a closed surface, depending on the context. But it seems the textbook I use employ that notation even when the line/surface integral is not over a closed curve/surface.
 
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Yes, that symbol means the integral over a closed curve. I've never seen it used for the surface integral over a closed surface but I guess it could be. I would be very surprised if a textbook used that to indicate an integral over a curve that was NOT closed. Could you give an example of that?
 
Ok this is from the 7th Edn of Engineering Electromagnetics by William Hayt and John Buck, pg 212 in the chapter on time-invariant magnetic fields:

It follows that only the integral form of the Biot-Savart law can be verified experimentally,
\textbf{H} = \oint \frac{Id\textbf{L} \times \textbf{a}_R}{4\pi R^2}

I suppose that it might be explained that the current I would be flowing in a closed circuit and hence a closed path. But what is the interpretation of \oint as applied to surface integrals? Must it be a closed surface?
 
I've seen that in Gauss's Law:

\oint E\! dA = Q / \epsilon_o

And, yes, to my understanding it must be a closed surface.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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