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Precalculus Mathematics Homework Help
Matrices and infinite solutions
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[QUOTE="lendav_rott, post: 4499928, member: 224893"] You need a fixed value of H in which case the 2 lines will always intersect. Since it's a 2d world I would go about it showing a value of H in which case the 2 functions' ascension angle or whatever it's called is not the same. I already know the tan of the ascension angle is the coefficient of the argument. I would express both functions as Y and get: y = (8/-7)x -1 y = (-16/H)x + 14/H now all that's left is to show that (8/-7) =/= -16/H - I get that they are only equal if and only if H = 14. No matter what ever else H, except H=0, value will result in intersection or in other words will mean the system has a specific solution. Right now it seems to me the system is solveable unless H=14 or H=0. For the system to have Infinite amount of solutions for 1 specific value of H means that the 2 lines are coinciding? (is that the word I'm looking for?) Coinciding is a special case of parallel, but I just showed the lines are parallel only if H=14. I drew the 2 graphs when H=14, they are not coinciding and they never will, which means there is no real value of H in which case the system has infinite number of solutions. Disecting this with Cramer's method end up in a brickwall aswell, same story, coinciding is impossible and only parallel when H=14, but no real solutions for the system. [/QUOTE]
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Matrices and infinite solutions
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