Matrix Differential Equation with Generalized Eigenvectors

Click For Summary
The discussion revolves around solving a differential equation represented by a matrix with initial conditions. The user identifies two eigenvalues, both equal to 5, and finds the corresponding eigenvector. They proceed to find a generalized eigenvector using the formula (A - 5I)v_2 = v_1, resulting in v_2 = [0, 1]. The user seeks guidance on the form of the solution for their upcoming exam. Clarification on matrix notation and solution structure is requested.
patchwerk
Messages
3
Reaction score
0
Hey guys, need some quick help before an exam

I have a differential eqn.

x' = | 0 1 | *x , and initial conditions x(0) = |2|
| -25 10 | |3|

I find that there are two eigenvalues 5, and 5

The corresponding eigenvector to 5 is [1 5] (vertical)

So i need to find a generalized eigenvector,

I do so in the form

(A - 5lambda)v_2 = v_1

I then find that v_2 = [0 1 ] (vertically)

I don't know what form my solution should now be in

Please help, I have an exam at 7,

Thanks,

Evan
 
Physics news on Phys.org
the matrix is R1: 0 1 and R2: -25 10
and the IC is x(0) = R1:2 R2:13

sorry, not sure hwo to enter matrices
 
patchwerk said:
the matrix is R1: 0 1 and R2: -25 10
and the IC is x(0) = R1:2 R2:13

sorry, not sure hwo to enter matrices

R2: is 3 sorry!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
1K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K