Matrix Differential Equation with Generalized Eigenvectors

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SUMMARY

The discussion centers on solving a matrix differential equation represented by the system x' = | 0 1 | * x with initial conditions x(0) = | 2 | and | 3 |. The eigenvalues identified are both 5, with the corresponding eigenvector being [1, 5]. To find the generalized eigenvector, the user applies the formula (A - 5I)v_2 = v_1, resulting in v_2 = [0, 1]. The user seeks guidance on the appropriate form for the solution to the differential equation.

PREREQUISITES
  • Understanding of matrix differential equations
  • Knowledge of eigenvalues and eigenvectors
  • Familiarity with generalized eigenvectors
  • Basic proficiency in linear algebra concepts
NEXT STEPS
  • Study the method for solving matrix differential equations using eigenvalues and eigenvectors
  • Learn about the construction of solutions involving generalized eigenvectors
  • Explore the application of the Jordan form in solving differential equations
  • Review examples of initial value problems in linear systems
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Students preparing for exams in differential equations, mathematicians focusing on linear algebra, and educators teaching matrix theory and its applications.

patchwerk
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Hey guys, need some quick help before an exam

I have a differential eqn.

x' = | 0 1 | *x , and initial conditions x(0) = |2|
| -25 10 | |3|

I find that there are two eigenvalues 5, and 5

The corresponding eigenvector to 5 is [1 5] (vertical)

So i need to find a generalized eigenvector,

I do so in the form

(A - 5lambda)v_2 = v_1

I then find that v_2 = [0 1 ] (vertically)

I don't know what form my solution should now be in

Please help, I have an exam at 7,

Thanks,

Evan
 
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the matrix is R1: 0 1 and R2: -25 10
and the IC is x(0) = R1:2 R2:13

sorry, not sure hwo to enter matrices
 
patchwerk said:
the matrix is R1: 0 1 and R2: -25 10
and the IC is x(0) = R1:2 R2:13

sorry, not sure hwo to enter matrices

R2: is 3 sorry!
 

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