Matrix, eigenvalues and diagonalization

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Homework Help Overview

The discussion revolves around the diagonalization of a matrix, specifically focusing on the eigenvalues and the conditions under which a matrix can be diagonalized. The matrix in question has eigenvalues k=3 and k=-1.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of having a double eigenvalue and discuss the necessity of independent eigenvectors for diagonalization. There is a focus on determining the number of independent solutions associated with the eigenvalue -1.

Discussion Status

Participants are actively engaging with the problem, with some offering insights into the relationship between eigenvalues and diagonalization. There is an acknowledgment of the need to demonstrate the lack of independent eigenvectors corresponding to the double eigenvalue.

Contextual Notes

There is a mention of the characteristic polynomial and its roots, which is relevant to the discussion of eigenvalues and their implications for diagonalization. The original poster appears to be seeking clarification on the next steps in their analysis.

jkeatin
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Matrix A= 1 2 0
2 1 0
2 -1 3



i got eigenvalues k=3 k=-1 what do i do after that to prove it is not able to be diagonalized
 
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jkeatin said:
i got eigenvalues k=3 k=-1 what do i do after that to prove it is not able to be diagonalized

Hi jkeatin! :smile:

-1 is a is a double eigenvalue …

so just plug -1 in and solve, and show that there is only one independent solution. :wink:
 


The point is that an n by n matrix is diagonalizable if and only if it has n independent eigenvectors. Since -1 is a double root of the characteristic polynomial, the matrix may not have two independent eigenvectors corresponding to eigenvalue -1. That is what you need to prove.
 


thanks guys, got it!
 

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