Matrix problem help. solve the remaining equation and find the value(s) for x

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Homework Help Overview

The discussion revolves around a matrix equation involving variables x, a, b, and c, specifically focusing on finding the values of x that satisfy the determinant of the matrix being equal to zero.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the process of taking the determinant of the matrix and setting it to zero. There is confusion about whether the resulting expression leads to a quadratic equation and how to interpret the variables involved.

Discussion Status

Some participants confirm the approach of setting the determinant to zero and discuss the implications of the quadratic equation. There is acknowledgment that numerical solutions depend on the specific values of a, b, and c.

Contextual Notes

Participants note that without specific values for a, b, and c, the solutions will remain in terms of these variables, leading to expressions rather than numerical answers.

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Homework Statement


| x 0 c|
| -1 x b| = 0
| 0 -1 a|

Homework Equations





The Attempt at a Solution


As best as I can tell I would end up with x * (xa - (-1b)) and -1c and then I would end up with Ax^2 + BX + C which leaves me confused am I looking at a quadratic equation for the answer or is there a way to get numerical values out of it?
 
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flatty said:

Homework Statement


| x 0 c|
| -1 x b| = 0
| 0 -1 a|

Homework Equations





The Attempt at a Solution


As best as I can tell I would end up with x * (xa - (-1b)) and -1c and then I would end up with Ax^2 + BX + C which leaves me confused am I looking at a quadratic equation for the answer or is there a way to get numerical values out of it?
Your problem statement says that the determinant of your matrix is zero.

What equation represents this?
 
I presume you are taking the determinant and setting it equal to zero. If so, what you've done looks right. Remember the solution to a quadratic equation? Also, you can only get a numerical answer if you know the values of a,b,c. Otherwise, the answer will be an expression involving a,b,c.
 
0=x*(xa-(-1b))-(-1*c)

I am using det(a)=A11(A22*A33-A23*A32)-A12(A21*A33-A23*A31)+A13(A21*A32-A22*A31)

Yes it is equal to zero sorry, new here.

Ax^2+bx+c=0 so I am assuming my answer would be x = [-b ± √(b^2 - 4ac) ]/2a
 
thanks
 

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