Matrix Theory (Matrix Inverse test question)

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SUMMARY

The discussion centers on finding the inverse of a 3x3 matrix 'A' given the equation (\mathbf{A} + \mathbf{I})^{2} = \mathbf{0}, where 'I' is the identity matrix and '0' is the zero matrix. The initial approach incorrectly treated the equation as a standard algebraic one, leading to the conclusion that 'A' equals the negative identity matrix. However, it is clarified that while matrices can be manipulated algebraically, the implication that B^2 = 0 necessitates B = 0 is false, emphasizing the unique properties of matrix operations.

PREREQUISITES
  • Understanding of matrix operations and properties
  • Familiarity with 3x3 matrices and identity matrices
  • Knowledge of algebraic manipulation of matrices
  • Concept of matrix commutativity in multiplication
NEXT STEPS
  • Study the properties of matrix inverses and their computation
  • Learn about the implications of nilpotent matrices (B^2 = 0)
  • Explore the concept of matrix commutativity and its applications
  • Practice solving matrix equations involving identity and zero matrices
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Students studying linear algebra, mathematicians interested in matrix theory, and educators teaching matrix operations and properties.

mateomy
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I was asked this question on a test I just took and I was kinda stumped. I worked it out but I think I did it incorrectly so I was hoping for some input. Thanks.


'A' is a 3x3 matrix and 'I' is the identity matrix for a 3x3. Find the Inverse of 'A' given:

<br /> (\mathbf{A}\,+\,\mathbf{I})^{2}\,=\,\mathbf{0}<br />

Where '0' is the zero matrix.

So what I did (probably ignorantly) was treat it like any standard algebraic equation; took the radical of both sides, and subtracted the Identity from each side. So I had the zero matrix minus the standard identity 3x3. So I ended up getting a negative identity matrix on the right hand side. So I can see that 'A' equals the negative of an identity matrix. So to find the identity of that I put my 'A' next to and identity to solve in the standard fashion, for the identity of A. Which just happened to be, again, a negative of a 3x3 identity matrix.

Sorry I didn't feel like Latex'ing out all the matrix work but I think it can be followed by what I wrote.

Thanks again.
 
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mateomy said:
I was asked this question on a test I just took and I was kinda stumped. I worked it out but I think I did it incorrectly so I was hoping for some input. Thanks.


'A' is a 3x3 matrix and 'I' is the identity matrix for a 3x3. Find the Inverse of 'A' given:

<br /> (\mathbf{A}\,+\,\mathbf{I})^{2}\,=\,\mathbf{0}<br />

Where '0' is the zero matrix.

So what I did (probably ignorantly) was treat it like any standard algebraic equation; took the radical of both sides, and subtracted the Identity from each side. So I had the zero matrix minus the standard identity 3x3. So I ended up getting a negative identity matrix on the right hand side. So I can see that 'A' equals the negative of an identity matrix. So to find the identity of that I put my 'A' next to and identity to solve in the standard fashion, for the identity of A. Which just happened to be, again, a negative of a 3x3 identity matrix.

Sorry I didn't feel like Latex'ing out all the matrix work but I think it can be followed by what I wrote.

Thanks again.

If B is a matrix and B^2 = 0, that does NOT imply that B must be zero; matrices do not behave like real numbers in all respects. However, you _can_ use standard algebra to expand (A+I)^2, because the matrices A and I commute under multiplication (that is, AI = IA), and you _can_ use AB+AC = A(B+C), etc.

RGV
 

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