Max amplitude of superposition of 2 waves

rc2008
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Homework Statement
Max amplitude of superposition of 2 waves
Relevant Equations
Find amplitude of superposition of 2 waves, 4.6sin 2pi()*5.4x and 3.2sin2pi()*10x,
My answer is simply 4.6+ 3.2 = 7.8m , correct me if I am wrong.

If it's 4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)##, then the max amplitude should be sqrt(4.6^2 + 3.2^2) = 5.6m, correct me if I am wrong.
 
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Hi, and :welcome: ,

I can't even read your formulas (surely you don't mean ##(\sin 2)\ \pi \ 10x## but what you do mean is a guess.

Use some more brackets and learn to use ##\TeX##

1731756369373.png

And your two claims cannot both be correct !

rc2008 said:
If it's 4.6cos2pi()*5.4x and 3.2sin2pi()*10x, then the max amplitude should be sqrt(4.6^2 + 3.2^2) = 5.6
What mathematical rule are you using here ?

And a graph of the superposition easily proves it's wrong !

##\ ##
 
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What do you get for the amplitude of ##\cos x+\sin x\ ## ? For ##\cos x+\sin (2x)\ ## ?

##\ ##
 
BvU said:
What do you get for the amplitude of ##\cos x+\sin x\ ## ? For ##\cos x+\sin (2x)\ ## ?

##\ ##

For ##\cos x+\sin x\ ##, i would get 2 , simply because ##sqrt(1+1)## = 2
 
BvU said:
What do you get for the amplitude of ##\cos x+\sin x\ ## ? For ##\cos x+\sin (2x)\ ## ?

##\ ##
For ##\cos x+\sin (2x)\ ##, I would also get 2, simply because of shape of ##\cos (x) \## will coincide after some time.

For my case of
4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)##
, I am not sure whether they will coincide or not because 10 is not a whole numer of multiplier of 5.4
 
rc2008 said:
For ##\cos x+\sin x\ ## , i would get 2 , simply because sqrt(1+1) = 2
sqrt (1+1) = 2 ?
Ah, you are learning ##\TeX## ! Bravo !


rc2008 said:
For ##\cos x+\sin (2x)\ ##, I would also get 2, simply because of shape of ##\cos (x) \## will coincide after some time.

For my case of
4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)##
, I am not sure whether they will coincide or not because 10 is not a whole numer of multiplier of 5.4


You must have seen plots of ##\sin x## and ##\cos x##.

1731771857806.png


## \cos x+\sin (2x)\ ## looks like this:

1731772042402.png

Functions coincide some times (with y=0), peaks don't !
 
rc2008 said:
For ##\cos x+\sin x\ ##, i would get 2 , simply because ##sqrt(1+1)## = 2
That's not true at all.
##\sqrt{1 + 1} = \sqrt 2##.

Here's my LaTeX before it gets rendered by the browser: ##\sqrt{1 + 1} = \sqrt 2##

Notice the backslash in front of the sqrt command.
 
rc2008 said:
My answer is simply 4.6+ 3.2 = 7.8m , correct me if I am wrong.

What condition(s) has(have) to be fulfilled for this 7.8 to be the value of ##4.6 \cos(2\pi*5.4x) + 3.2\sin(2\pi*10x)## ?
And for -7.8 ?

##\ ##
 
4.6 \cos(2\pi*5.4x) + 3.2\sin(2\pi*10x) is periodic, because 5.4 is a rational multiple of 10. (It would be easier to write this as 4.6\cos(10.8\pi x) + 3.2\sin(20\pi x).)

It is not in general possible to reduce sines of different frequencies to an expression of the form R\sin (\alpha x + \beta). It might be possible to obtain the zeros of the derivative analytically, but most likely a numerical method will be required.
 
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  • #10
Mark44 said:
That's not true at all.
##\sqrt{1 + 1} = \sqrt 2##.

Here's my LaTeX before it gets rendered by the browser: ##\sqrt{1 + 1} = \sqrt 2##

Notice the backslash in front of the sqrt command.
How do you prevent the Latex from rendering, even when using tags?
 
  • #11
WWGD said:
How do you prevent the Latex from rendering, even when using tags?
For the stuff I don't want to render, I color the first # of each group black using the BBCode color tool.
 
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