Max amplitude of superposition of 2 waves

Click For Summary
The maximum amplitude of the superposition of the waves 4.6cos(2π*5.4x) and 3.2sin(2π*10x) is calculated as sqrt(4.6^2 + 3.2^2), resulting in 5.6m, rather than the initially suggested 7.8m. The discussion highlights the importance of understanding the conditions under which amplitudes can be summed directly. It is noted that the periodic nature of the combined function arises from the rational relationship between the frequencies. Additionally, there is confusion regarding the use of LaTeX for mathematical expressions, with participants discussing formatting issues. The conversation emphasizes the need for clarity in mathematical representation and understanding wave superposition principles.
rc2008
Messages
11
Reaction score
0
Homework Statement
Max amplitude of superposition of 2 waves
Relevant Equations
Find amplitude of superposition of 2 waves, 4.6sin 2pi()*5.4x and 3.2sin2pi()*10x,
My answer is simply 4.6+ 3.2 = 7.8m , correct me if I am wrong.

If it's 4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)##, then the max amplitude should be sqrt(4.6^2 + 3.2^2) = 5.6m, correct me if I am wrong.
 
Last edited:
Physics news on Phys.org
Hi, and :welcome: ,

I can't even read your formulas (surely you don't mean ##(\sin 2)\ \pi \ 10x## but what you do mean is a guess.

Use some more brackets and learn to use ##\TeX##

1731756369373.png

And your two claims cannot both be correct !

rc2008 said:
If it's 4.6cos2pi()*5.4x and 3.2sin2pi()*10x, then the max amplitude should be sqrt(4.6^2 + 3.2^2) = 5.6
What mathematical rule are you using here ?

And a graph of the superposition easily proves it's wrong !

##\ ##
 
Last edited:
What do you get for the amplitude of ##\cos x+\sin x\ ## ? For ##\cos x+\sin (2x)\ ## ?

##\ ##
 
BvU said:
What do you get for the amplitude of ##\cos x+\sin x\ ## ? For ##\cos x+\sin (2x)\ ## ?

##\ ##

For ##\cos x+\sin x\ ##, i would get 2 , simply because ##sqrt(1+1)## = 2
 
BvU said:
What do you get for the amplitude of ##\cos x+\sin x\ ## ? For ##\cos x+\sin (2x)\ ## ?

##\ ##
For ##\cos x+\sin (2x)\ ##, I would also get 2, simply because of shape of ##\cos (x) \## will coincide after some time.

For my case of
4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)##
, I am not sure whether they will coincide or not because 10 is not a whole numer of multiplier of 5.4
 
rc2008 said:
For ##\cos x+\sin x\ ## , i would get 2 , simply because sqrt(1+1) = 2
sqrt (1+1) = 2 ?
Ah, you are learning ##\TeX## ! Bravo !


rc2008 said:
For ##\cos x+\sin (2x)\ ##, I would also get 2, simply because of shape of ##\cos (x) \## will coincide after some time.

For my case of
4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)##
, I am not sure whether they will coincide or not because 10 is not a whole numer of multiplier of 5.4


You must have seen plots of ##\sin x## and ##\cos x##.

1731771857806.png


## \cos x+\sin (2x)\ ## looks like this:

1731772042402.png

Functions coincide some times (with y=0), peaks don't !
 
rc2008 said:
For ##\cos x+\sin x\ ##, i would get 2 , simply because ##sqrt(1+1)## = 2
That's not true at all.
##\sqrt{1 + 1} = \sqrt 2##.

Here's my LaTeX before it gets rendered by the browser: ##\sqrt{1 + 1} = \sqrt 2##

Notice the backslash in front of the sqrt command.
 
rc2008 said:
My answer is simply 4.6+ 3.2 = 7.8m , correct me if I am wrong.

What condition(s) has(have) to be fulfilled for this 7.8 to be the value of ##4.6 \cos(2\pi*5.4x) + 3.2\sin(2\pi*10x)## ?
And for -7.8 ?

##\ ##
 
4.6 \cos(2\pi*5.4x) + 3.2\sin(2\pi*10x) is periodic, because 5.4 is a rational multiple of 10. (It would be easier to write this as 4.6\cos(10.8\pi x) + 3.2\sin(20\pi x).)

It is not in general possible to reduce sines of different frequencies to an expression of the form R\sin (\alpha x + \beta). It might be possible to obtain the zeros of the derivative analytically, but most likely a numerical method will be required.
 
Last edited:
  • #10
Mark44 said:
That's not true at all.
##\sqrt{1 + 1} = \sqrt 2##.

Here's my LaTeX before it gets rendered by the browser: ##\sqrt{1 + 1} = \sqrt 2##

Notice the backslash in front of the sqrt command.
How do you prevent the Latex from rendering, even when using tags?
 
  • #11
WWGD said:
How do you prevent the Latex from rendering, even when using tags?
For the stuff I don't want to render, I color the first # of each group black using the BBCode color tool.