Max Area Rectangle on y=cosx Curve

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SUMMARY

The discussion focuses on finding the dimensions of the rectangle with the largest area that lies on the curve y=cos(x) and has its base on the x-axis. The area A is defined as A=2x*cos(x), where x is the x-coordinate of the rectangle's vertices. To maximize the area, the derivative of A with respect to x is taken and set to zero, leading to the transcendental equation cot(x)=x. A suggested trial solution is x=π/4, where cot(π/4)=1, indicating that further numerical methods or calculator solutions are necessary to achieve the desired precision of five decimal places.

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Homework Statement


find, correct to five decimal places, the dimensions of the rectangle of largest area that has its base on the x-axis and its other two vertices above the x-axis and lying on the curve y=cosx


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The Attempt at a Solution

 
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this is a standard calc min/max problem. First make an equation of what you want to maximize
A=bh
the base is 2 times your x coordinate, and your height is just y so:
A= 2xy
now substute in your restraint equation y = cos(x)
A=2xcos(x)
now take the derivative with respect to x and set equal to zero. The solution should be the correct x value
 
I'm getting a transcendental equation out of this cot(x)=x, guess you have to solve with your calculator from there unless I am making some mistake somewhere, usually these types of problems are a little cleaner to solve.
 
LogicalTime said:
I'm getting a transcendental equation out of this cot(x)=x, guess you have to solve with your calculator from there unless I am making some mistake somewhere, usually these types of problems are a little cleaner to solve.

That's what I get, so I think you're on the right track. A trial solution is x = pi/4, for which cot(pi/4) = 1. Those values aren't too far apart. I would keep trying different values, looking for values for which x and cot(x) are closer together, stopping when I get them to agree in 5 decimal places.
 

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