Max Breaking Force on Car & Friction of Mop: Coefficient, Mass, Angle

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SUMMARY

The maximum breaking force obtainable for a car with a mass of 1600 kg on a level road is calculated using the coefficient of static friction of 0.62, resulting in a force of 9920 N. On an 8.6° downgrade, the breaking force is adjusted to account for gravitational components, yielding a maximum breaking force of approximately 10,000 N. For the mop scenario, the force required to slide the mop with uniform velocity is determined by the coefficients of static and kinetic friction, with a critical angle θ0 established for sliding conditions.

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  • Understanding of Newton's laws of motion
  • Familiarity with friction coefficients (static and kinetic)
  • Basic trigonometry for angle calculations
  • Knowledge of force and mass relationships in physics
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  • Calculate breaking forces on various inclines using different friction coefficients
  • Explore the relationship between angle and friction in practical applications
  • Investigate the effects of mass on frictional force in different scenarios
  • Learn about the dynamics of sliding objects and the role of friction in motion
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The coefficient of static friction between the tires of a car and dry road is 0.62. The mass of the car is 1600 kg. What maximum breaking force is obtainable (a) on a level road and (b) 8.6° downgrade?

The handle of a floor mop of mass m makes an angle θ with the vertical direction. Let μk be the coefficient of kinetic friction between mop and floor and μs the coefficient of static friction between mop and floor. Neglect the mass of the handle. (a) Find the magnitude of the force F directed along the handle required to slide the mop with uniform velocity across the floor. (b) Show that θ is smaller than a certain θ0 of the mop cannot be made to slide across the floor no matter how great a force is directed along the handle. What is angle θ0?
 
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