Max Energy of UV Light Photon in Compton Collision

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SUMMARY

The maximum energy a photon of UV light with a wavelength of 320 nm can transfer to an electron during a Compton collision is calculated using the Compton equation. By setting cos(θ) to -1, the change in wavelength (Δλ) is determined to be 0.00486 nm. The momentum is calculated using the formula p = h/λ for both the initial and final wavelengths. The energy transfer is then derived using the equation E = hc/λ, with the differential energy change expressed as dE = -hc dλ/λ².

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  • Understanding of Compton scattering principles
  • Familiarity with the Compton equation
  • Knowledge of photon momentum calculations
  • Basic grasp of energy-wavelength relationships in quantum mechanics
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What is the maximum energy a photon of UV light ( lamda= 320 nm) can transfer to an electron in a Compton collision?

I used the Compton eq. and set cos= -1 and found the change in lamda to be 0.00486 nm. then using p=h/lamda where p is the momentum, i found the momentum for when lamda is 320 nm and 0.00486 nm. then I added the two momentums. How do I the energy from here?
 
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E=hc/\lambda.
dE=-hc d\lambda/\lambda^2.
 
For light E = h[itex]\nu[/itex] = pc, where E is energy and p is momentum.
 

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