(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A uniform 300-kg beam, 6 m long, is freely pivoted at P. The beam is supported in a horizontal position by a light strut, 5 m long, which is freely pivoted at Q and is loosely pinned to the beam at R. A load of mass is suspended from the end of the beam at S. A maximum compression of 23,000 N in the strut is permitted, due to safety. In Fig. 11.1, the maximum mass M of the load is closest to:

2. Relevant equations

Net Torque=0

Net Force=0

3. The attempt at a solution

I tried adding up all of the torque moments and then setting them equal to 23,000N.

300(9.8)(3m)+0(Pivot arm)+6m(mg for the mass)=23,000

Then I set that net torque equal to 23,000, isolated force of the mass, and divided by 9.8 m/s^2 in order to find the maximum mass. It's still wrong, and I don't know where to go from here

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Torque equilbrium involving support rod?

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