needhelp83 Messages 193 Reaction score 0 Thread starter Mar 3, 2008 #1 The largest memory space that can be addressed by 18 addressing bits is... Is there a formula for this perhaps?
The largest memory space that can be addressed by 18 addressing bits is... Is there a formula for this perhaps?
chroot Staff Emeritus Science Advisor Gold Member Messages 10,270 Reaction score 45 Mar 3, 2008 #2 How many different combinations of 18 ones and zeros are there? - Warren
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Mar 4, 2008 #5 Assuming that each "memory location" holds one byte, yes.
Mike Cookson Messages 84 Reaction score 0 Mar 4, 2008 #7 Something to note - while you might be able to have addresses going all the way up to 2^18 a lot of chips do not have memory locations for all of the addresses. Such as variants in the PIC16F8X range.
Something to note - while you might be able to have addresses going all the way up to 2^18 a lot of chips do not have memory locations for all of the addresses. Such as variants in the PIC16F8X range.
needhelp83 Messages 193 Reaction score 0 Mar 6, 2008 #8 I noticed in a Digital Circuits book that with 18 address leads it should be 256K. So where does my 262,144 come from with 2^18. Just a thought?
I noticed in a Digital Circuits book that with 18 address leads it should be 256K. So where does my 262,144 come from with 2^18. Just a thought?
chroot Staff Emeritus Science Advisor Gold Member Messages 10,270 Reaction score 45 Mar 6, 2008 #9 256 * 1,024 = 262,144. The "k" in this context means 1,024, not 1,000. - Warren