Max/Min f subject to g: Lagrange Multipliers

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Homework Help Overview

The discussion revolves around finding the maximum and minimum values of a function \( f(x,y,z) = \frac{1}{4}x^2 + \frac{1}{9}y^2 + z^2 \) subject to a constraint defined by \( g(x,y,z) = x^2 + y^2 + z^2 - 1 = 0 \). Participants are exploring the method of Lagrange multipliers to solve this constrained optimization problem.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting up the Lagrange function and finding its partial derivatives. There are questions about the conditions for maxima and minima, as well as the implications of setting the derivatives equal to zero. Some participants suggest checking notes for conditions that must be satisfied for extrema to exist.

Discussion Status

The discussion is ongoing, with participants actively engaging in the process of deriving the necessary conditions for critical points. There is a focus on understanding the implications of the equations derived from the Lagrange function and the constraints imposed by the problem.

Contextual Notes

Participants note the requirement that not all variables \( x, y, z \) can be zero due to the constraint \( x^2 + y^2 + z^2 = 1 \). There is an acknowledgment of the need for rest and the impact of fatigue on the problem-solving process.

terminal.velo
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Homework Statement



Find max/min of f subject to constraint: x^2+y^2+z^1 = 1


Homework Equations




f(x,y,z) = 1/4*x^2 + 1/9*y^2 + z^2
g(x,y,z) = x^2 + y^2 + z^2 - 1

The Attempt at a Solution



L = 1/4*x^2 + 1/9*y^2 + z^2 - λ(x^2 + y^2 + z^2 - 1)
Lx = 2/4*x - λ*x*2
Ly = 2/9*y - λ*2*y
Lz = 2*z - λ*2*z
 
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terminal.velo said:

Homework Statement



Find max/min of f subject to constraint: x^2+y^2+z^1 = 1


Homework Equations




f(x,y,z) = 1/4*x^2 + 1/9*y^2 + z^2
g(x,y,z) = x^2 + y^2 + z^2 - 1

The Attempt at a Solution



L = 1/4*x^2 + 1/9*y^2 + z^2 - λ(x^2 + y^2 + z^2 - 1)
Lx = 2/4*x - λ*x*2
Ly = 2/9*y - λ*2*y
Lz = 2*z - λ*2*z

Correct so far. What should be the partial derivatives at a minimum/maximum?

ehild
 
I don't know, the lecturer told us to solve the rest of the problem at home.
 
Well, check your notes, what is the condition that a minimum or maximum exist?

ehild
 
All 3 derivates of L (Lx, Ly, Lz) have to equal zero, to find the λ, then the x/y/z for critical points of f(x,y,z)

Lx = 2/4*x - λ*x*2 = 0
Ly = 2/9*y - λ*2*y = 0
Lz = 2*z - λ*2*z = 0
 
OK, factorize the left hand sides.

ehild
 
2x(1/4 - λ) = 0
2y(1/9 - λ) = 0
2z(1 - λ) = 0

EDIT: I'm in a bit of a funk, apologies! (lectures from 8am 'til 3pm)
 
terminal.velo said:
2x(1/4 - λ) = 0
2y(1/9 - λ) = 0
2z(1 - λ) = 0

EDIT: I'm in a bit of a funk, apologies! (lectures from 8am 'til 3pm)

So you need some rest, without Maths... :smile:
Anyway: you can omit the factors 2. All your equations are products, equal to zero. That means, one of the two factors must be zero in each equation. More than one factor containing lambda can not be zero, it would mean contradiction. Can all x, y,z equal to zero? Remember, you have the condition that x2+y2+z2=1.

ehild
 

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