Max Temperature Variation in Charles' Law Oxygen Gas Problem

[Speedking96]

Homework Statement

A syringe with a maximum volume of 60 ml takes in a 14.5 ml sample of oxygen gas at 24.3 degrees Celsius. What maximum variation in temperature does the oxygen undergo before the piston is completely pushed out of the syringe?

Homework Equations

(Initial Volume / Initial Temperature) = (Final Volume / Final Temp)

The Attempt at a Solution

(0.0145 L / 516.45 K) = ( 0.06 L / Final Temp)

Final Temp = 2137 K

Variation = 2137 - 516.45 = 1620.55 K = 1347.4 degrees Celsius

I feel that I correctly did the problem but I have some doubts because the answer seems unintuitive.

Thanks in advance for the help.

 

[Saitama]

Homework Statement

A syringe with a maximum volume of 60 ml takes in a 14.5 ml sample of oxygen gas at 24.3 degrees Celsius. What maximum variation in temperature does the oxygen undergo before the piston is completely pushed out of the syringe?

Homework Equations

(Initial Volume / Initial Temperature) = (Final Volume / Final Temp)

The Attempt at a Solution

(0.0145 L / 516.45 K) = ( 0.06 L / Final Temp)

Final Temp = 2137 K

Variation = 2137 - 516.45 = 1620.55 K = 1347.4 degrees Celsius

I feel that I correctly did the problem but I have some doubts because the answer seems unintuitive.

Thanks in advance for the help.

How do you get 516.45 K as the initial temperature?

What is (273+24.3)?