Chemistry Help - Using the Gas Laws

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SUMMARY

The discussion focuses on applying gas laws to determine the final pressure of an ideal gas when its temperature is increased while keeping the volume constant. The initial conditions are 1.00 atm, 20.0 degrees Celsius, and 1.00 L. Using Guy-Lussac's Law (P1/T1 = P2/T2), the final pressure can be calculated after raising the temperature to 200.0 degrees Celsius. The correct application of this law yields a final pressure of approximately 10.0 atm.

PREREQUISITES
  • Understanding of ideal gas behavior
  • Familiarity with gas laws: Boyle's Law, Charles' Law, and Guy-Lussac's Law
  • Basic algebra for solving equations
  • Knowledge of temperature scales (Celsius to Kelvin conversion)
NEXT STEPS
  • Study the derivation and applications of Guy-Lussac's Law in detail
  • Explore real-world applications of gas laws in engineering and chemistry
  • Learn about the Ideal Gas Law and its implications for various gases
  • Investigate the effects of non-ideal behavior in gases at high pressures and temperatures
USEFUL FOR

Students studying chemistry, particularly those focusing on thermodynamics and gas laws, as well as educators looking for practical examples of gas behavior under varying conditions.

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Homework Statement



This figure (file attached) shows a container that is sealed at the top by a movable piston. Inside the container is a ideal gas at 1.00 atm, 20.0 degrees Celsius, and 1.00 L.

The gas sample has now returned to its original state of 1.00 atm, 20.0 degrees Celsius and 1.00 L. What will the pressure become if the temperature of the gas is raised to 200.0degrees celsius and the piston is not allowed to move?

Homework Equations



Boyle's Law P_1V_1 = P_2V_2
or
Charles' Law V_1/T_1 = V_2/T_2

The Attempt at a Solution



Okay, in order for the piston not to move, this means that the volume must remain at 1.00 L. What I don't know what to do is how to relate temperature and pressure to solve for the final pressure.
 

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Guy-Lussacs Law P1/T1 = P2/T2
 

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