Max Vertical Reach at Back Wall: Solving Projectile Problem

  • Thread starter Thread starter xL0VEN0TE
  • Start date Start date
  • Tags Tags
    Projectile
Click For Summary
SUMMARY

The discussion focuses on solving a projectile problem to determine the maximum vertical reach at a back wall, incorporating an initial standing reach. The key equations utilized are d = vit + 1/2at² and vf² = vi² + 2ad. A ball is launched at a velocity of 20 m/s at a 60-degree angle. The conversation emphasizes the importance of including diagrams to clarify variables and the need for a qualitative analysis comparing terrestrial and lunar jumping dynamics.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic knowledge of angles in physics
  • Ability to analyze qualitative differences in physics scenarios
NEXT STEPS
  • Study the derivation of kinematic equations in projectile motion
  • Learn how to create and interpret motion diagrams
  • Investigate the effects of gravity on jumping in different environments
  • Explore advanced projectile motion problems using simulation tools
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding projectile motion and its applications in varying gravitational contexts.

xL0VEN0TE
Messages
3
Reaction score
0

Homework Statement


Finding the maximum vertical reach at the back wall.
This should be viewed as a peak height projectile problem (added to an
initial standing reach). Are diagrams
included to show the meaning of each variable? Are reasonable and unique
values used? Is the maximum vertical reach found? Is there a qualitative
analysis about the many dramatic differences between Terrestrial and Lunar jumping?

Homework Equations


d= vit+1/2at^2
vf^2=vi^2+2ad

The Attempt at a Solution


ball launched at 20 m/s. 60 degree angle.
 
Physics news on Phys.org
Welcome to PF!

Hi xL0VEN0TE! Welcome to PF! :wink:

What exactly is your question (and where is the wall)? :confused:

Anyway, show us what you've done, and where you're stuck, and then we'll know how to help. :smile:
 
Thanks. Sorry, I'm still kind of new to this website.
I just need to create a projectile problem with that info given.
 

Similar threads

Replies
7
Views
2K
Replies
19
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 22 ·
Replies
22
Views
5K
Replies
12
Views
3K
Replies
3
Views
4K