1. The problem statement, all variables and given/known data A projectile is launched at 110.0 m/s at 40.0° above the horizontal off a cliff that is 250.0 m above sea level. After 4.00 s of flight, this projectile launches a second projectile at 50.0 m/s directed at 15.0° below the horizontal. a) Find the max height of the second projectile relative to seal level. b) Find the range of the second projectile when it reaches sea level. 2. Relevant equations In x-direction: x=(vicos∅)t , vi=vf , vix= vicos∅ In y-direction: y=yi + vit + .5at^2 , v=vi+at , vi=visin∅ 3. The attempt at a solution I got the answer to part a, 472m. However, I am lost at trying to find an answer to part b. Using x=(vi)(t)=(110cos40)(4)=337m, I used that as the range the first projectile goes before releasing the second projectile. Now in trying to find how far the second projectile goes when it hits sea level, I plan on adding that to the first range. Any thoughts?