Maxima and Minima (vector calculus)

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SUMMARY

The discussion focuses on the function \( f(x, y) = (x^2 + y^2)e^{-(x^2 + y^2)} \) and its local maximum on the unit circle defined by \( x^2 + y^2 = 1 \). Participants explore how to interpret the graph of this function and the implications of its cylindrical coordinates representation \( f(r, \theta) = r^2 e^{-r^2} \). Additionally, they discuss methods for plotting this function using tools like R and GNU Octave, emphasizing the simplicity of visualizing it through graphing calculators.

PREREQUISITES
  • Understanding of vector calculus concepts, specifically maxima and minima.
  • Familiarity with cylindrical coordinates in mathematical functions.
  • Basic knowledge of graphing functions in R and GNU Octave.
  • Experience with interpreting graphical representations of mathematical functions.
NEXT STEPS
  • Learn how to plot functions in R using the ggplot2 package.
  • Explore the use of GNU Octave for visualizing mathematical functions.
  • Study the properties of local maxima and minima in multivariable calculus.
  • Investigate the implications of cylindrical coordinates in vector calculus.
USEFUL FOR

Students and educators in mathematics, particularly those studying vector calculus, as well as data scientists and analysts interested in visualizing complex functions using R or GNU Octave.

WMDhamnekar
MHB
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Hi, Hi,

Author said If we look at the graph of $ f (x, y)= (x^2 +y^2)*e^{-(x^2+y^2)},$ as shown in the following Figure it looks like we might have a local maximum for (x, y) on the unit circle $ x^2 + y^2 = 1.$

1649834173266.png
But when I read this graph, I couldn't guess that the stated function have a local maximum on the unit circle $ x^2 + y^2=1$

1)I want to know what did author grasp in the above figure which compelled him to make the aforesaid statement?

2) How to plot this function in 'R' or in 'GNU OCTAVE' or in any graphing calculator ? Is it easy to plot $f(x,y)= (x^2+y^2)*e^{-(x^2+y^2)} ?$
 
Last edited:
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Do you notice that the only way x and y appear in that function is as "$x^2+y^2$"? In cylindrical coordinates we can write it as $f(r,\theta)= r^2e^{-r^2}$. If we write it as $y= x^2e^{x^2}$ its graph looks like this: <iframe src="https://www.desmos.com/calculator/oj7v5yfd0f?embed" width="500" height="500" style="border: 1px solid #ccc" frameborder=0></iframe>

Do you see what happens at x= 1 and x= -1? Imagine rotating that around the y-axis.
 

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